RBIT

Reverse Bits reverses the bit order in a 32-bit register.

It has encodings from the following instruction sets: A32 ( A1 ) and T32 ( T1 ) .

A1

313029282726252423222120191817161514131211109876543210
!= 111101101111(1)(1)(1)(1)Rd(1)(1)(1)(1)0011Rm
cond

A1

RBIT{<c>}{<q>} <Rd>, <Rm>

constant d = UInt(Rd); constant m = UInt(Rm); if d == 15 || m == 15 then UNPREDICTABLE;

T1

15141312111098765432101514131211109876543210
111110101001Rn1111Rd1010Rm

T1

RBIT{<c>}{<q>} <Rd>, <Rm>

constant d = UInt(Rd); constant m = UInt(Rm); constant n = UInt(Rn); // Armv8-A removes UNPREDICTABLE for R13 if m != n || d == 15 || m == 15 then UNPREDICTABLE;

CONSTRAINED UNPREDICTABLE behavior

If m != n, then one of the following behaviors must occur:

For more information about the constrained unpredictable behavior of this instruction, see Architectural Constraints on UNPREDICTABLE behaviors.

Assembler Symbols

<c>

See Standard assembler syntax fields.

<q>

See Standard assembler syntax fields.

<Rd>

Is the general-purpose destination register, encoded in the "Rd" field.

<Rm>

For encoding A1: is the general-purpose source register, encoded in the "Rm" field.

For encoding T1: is the general-purpose source register, encoded in the "Rm" field. It must be encoded with an identical value in the "Rn" field.

Operation

if ConditionPassed() then EncodingSpecificOperations(); bits(32) result; for i = 0 to 31 result<31-i> = R[m]<i>; R[d] = result;

Operational information

If CPSR.DIT is 1, this instruction has passed its condition execution check, and does not use R15 as either its source or destination:


Internal version only: isa v01_31, pseudocode v2024-03_rel ; Build timestamp: 2024-03-25T10:05

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