SMUSD, SMUSDX

Signed Multiply Subtract Dual performs two signed 16 x 16-bit multiplications. It subtracts one of the products from the other, and writes the result to the destination register.

Optionally, the instruction can exchange the halfwords of the second operand before performing the arithmetic. This produces top x bottom and bottom x top multiplication.

Overflow cannot occur.

It has encodings from the following instruction sets: A32 ( A1 ) and T32 ( T1 ) .

A1

313029282726252423222120191817161514131211109876543210
!= 111101110000Rd1111Rm01M1Rn
cond

Encoding for the SMUSD variant

Applies when (M == 0)

SMUSD{<c>}{<q>} {<Rd>,} <Rn>, <Rm>

Encoding for the SMUSDX variant

Applies when (M == 1)

SMUSDX{<c>}{<q>} {<Rd>,} <Rn>, <Rm>

Decode for all variants of this encoding

constant d = UInt(Rd); constant n = UInt(Rn); constant m = UInt(Rm); constant m_swap = (M == '1'); if d == 15 || n == 15 || m == 15 then UNPREDICTABLE;

T1

15141312111098765432101514131211109876543210
111110110100Rn1111Rd000MRm

Encoding for the SMUSD variant

Applies when (M == 0)

SMUSD{<c>}{<q>} {<Rd>,} <Rn>, <Rm>

Encoding for the SMUSDX variant

Applies when (M == 1)

SMUSDX{<c>}{<q>} {<Rd>,} <Rn>, <Rm>

Decode for all variants of this encoding

constant d = UInt(Rd); constant n = UInt(Rn); constant m = UInt(Rm); constant m_swap = (M == '1'); // Armv8-A removes UNPREDICTABLE for R13 if d == 15 || n == 15 || m == 15 then UNPREDICTABLE;

For more information about the constrained unpredictable behavior of this instruction, see Architectural Constraints on UNPREDICTABLE behaviors.

Assembler Symbols

<c>

See Standard assembler syntax fields.

<q>

See Standard assembler syntax fields.

<Rd>

Is the general-purpose destination register, encoded in the "Rd" field.

<Rn>

Is the first general-purpose source register, encoded in the "Rn" field.

<Rm>

Is the second general-purpose source register, encoded in the "Rm" field.

Operation

if ConditionPassed() then EncodingSpecificOperations(); constant operand2 = if m_swap then ROR(R[m],16) else R[m]; constant product1 = SInt(R[n]<15:0>) * SInt(operand2<15:0>); constant product2 = SInt(R[n]<31:16>) * SInt(operand2<31:16>); constant result = product1 - product2; R[d] = result<31:0>; // Signed overflow cannot occur


Internal version only: isa v01_32, pseudocode v2024-12_rel ; Build timestamp: 2024-12-16T10:54

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