Searched refs:divff (Results 1 – 1 of 1) sorted by relevance
26 u32 divr_val, divq_val, divf_val, divff, divfi; in decode_frac_pll() local70 divff = (pll_cfg1 & FRAC_PLL_FRAC_DIV_CTL_MASK) >> in decode_frac_pll()74 divf_val = 1 + divfi + divff / (1 << 24); in decode_frac_pll()
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